I had the need to reverse a JavaScript array, and here is what I did.

我需要反转JavaScript数组，这就是我所做的。

Given an array list:

给定一个数组list ：

const list = [1, 2, 3, 4, 5]

The easiest and most intuitive way is to call the reverse() method of an array.

最简单，最直观的方法是调用数组的reverse()方法。

This method alters the original array, so I can declare list as a const, because I don’t need to reassign the result of calling list.reverse() to it:

此方法会更改原始数组，因此我可以将list声明为const，因为我不需要将调用list.reverse()的结果重新分配给它：

const list = [1, 2, 3, 4, 5]list.reverse()//list is [ 5, 4, 3, 2, 1 ]

You can pair this method with the spread operator to first copy the original array, and then reversing it, so the original array is left untouched:

您可以将此方法与散布运算符配对使用，以首先复制原始数组，然后将其反转，因此原始数组将保持不变：

const list = [1, 2, 3, 4, 5]const reversedList = [...list].reverse()//list is [ 1, 2, 3, 4, 5 ]//reversedList is [ 5, 4, 3, 2, 1 ]

Another way is to use slice() without passing arguments:

另一种方法是使用slice()而不传递参数：

const list = [1, 2, 3, 4, 5]const reversedList = list.slice().reverse()//list is [ 1, 2, 3, 4, 5 ]//reversedList is [ 5, 4, 3, 2, 1 ]

but I find the spread operator more intuitive than slice().

但是我发现散布运算符比slice()更直观。

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